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Question

Chemistry Question on Electrochemistry

A current of 9.65 ampere flowing for 10 minutes deposits 3.0 g of the metal which is monovalent. The atomic mass of the metal is

A

10

B

50

C

30

D

96.5

Answer

50

Explanation

Solution

Q=ItQ = It =9.65×10×60= 9.65 \times 10\times 60 =5790C = 5790\,C M+monovalent metal+e1F,96500C>M1mole\underset{\text{monovalent metal}}{M^+} + \underset{1F , 96500\,C}{e} {->} \underset {1\,mole}{M} With 5790C5790 \,C, amount of metal deposited =3gm= 3\, gm With 96500C96500 \,C, amount of metal deposited =35790×96500 = \frac{3}{5790} \times 96500 =50g = 50\,g(equivalent weight) Atomic mass =50×= 50 \times valency =50×1=50= 50 \times 1 = 50 amu