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Question: A current of 5 ampere is flowing in a wire of length 1.5 metres. A force of 7.5 N acts on it when it...

A current of 5 ampere is flowing in a wire of length 1.5 metres. A force of 7.5 N acts on it when it is placed in a uniform magnetic field of 2 Tesla. The angle between the magnetic field and the direction of the current is

A

30∘30 ^ { \circ }

B

45°

C

60°

D

90°

Answer

30∘30 ^ { \circ }

Explanation

Solution

F=F = Bil sin⁡θ⇒7.5=2×5×1.5sin⁡θ⇒θ=30∘\sin \theta \Rightarrow 7.5 = 2 \times 5 \times 1.5 \sin \theta \Rightarrow \theta = 30 ^ { \circ }