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Physics Question on Current electricity

A current of 5 A5 \,A is passing through a metallic wire of cross-sectional area 4×10−6m24\times {{10}^{-6}}{{m}^{2}} . If the density of charge carriers of the wire is 5×10265\times {{10}^{26}} m−3,{{m}^{-3}}, the drift velocity of the electrons will be

A

1×102ms−11\times {{10}^{2}}m{{s}^{-1}}

B

1.56×10−2ms−11.56\times {{10}^{-2}}m{{s}^{-1}}

C

1.56×10−3ms−11.56\times {{10}^{-3}}m{{s}^{-1}}

D

1×10−2ms−11\times {{10}^{-2}}m{{s}^{-1}}

Answer

1.56×10−2ms−11.56\times {{10}^{-2}}m{{s}^{-1}}

Explanation

Solution

Drift velocity, vd=IneA{{v}_{d}}=\frac{I}{neA} ⇒\Rightarrow vd=5(5×1026)×(1.6×10−19)×(4×10−6){{v}_{d}}=\frac{5}{(5\times {{10}^{26}})\times (1.6\times {{10}^{-19}})\times (4\times {{10}^{-6}})} =1.56×10−2ms−1=1.56\times {{10}^{-2}}m{{s}^{-1}}