Question

A current of $4.8\, A$ is flowing in a conductor. The number of electrons passing per sec through the conductor will be

• A. $3 \times 10^{19}$
• B. $76.8 \times 10^{20}$
• C. $7.68 \times 10^{20}$
• D. $3 \times 10^{20}$

Answer 1

Answer: (A)

$3 \times 10^{19}$

Answer 2

Current $I=\frac{\text{Charge (Q)}}{\text{time (t)}}$ $I=\frac{ne}{t}$ or $\frac{n}{t}=\frac{I}{e}=\frac{\left(4.8 A\right)}{\left(1.6\times10^{-9} C\right)}$ $=3\times10^{19} / sec$