Question

A current of 2 A flows in a system of conductors as shown. The potential difference (V_A – V_B) will be

• A.
  • 2V
• B.
  • 1V
• C. – 1 V
• D. – 2 V

Answer 1

Answer: (B)

• 1V

Answer 2

In the given circuit 2A current divides equally at junction D along the paths DAC and DBC (each path carry 1A current).

Potential difference between D and A, V_D – V_A = 1 × 2 = 2 volt …. (i)

Potential difference between D and B, V_D – V_B = 1 × 3 = 3 volt ….. (ii)

On solving (i) and (ii) V_A – V_B = + 1 volt