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Question: A current of 10 ampere is flowing in a wire of length 1.5 m. A force of 15 N acts on it when it is p...

A current of 10 ampere is flowing in a wire of length 1.5 m. A force of 15 N acts on it when it is placed in a uniform magnetic field of 2 tesla. The angle between the magnetic field and the direction of the current is

A

30∘30 ^ { \circ }

B

45∘45 ^ { \circ }

C

60∘60 ^ { \circ }

D

90∘90 ^ { \circ }

Answer

30∘30 ^ { \circ }

Explanation

Solution

F=F = Bil sin⁡θ⇒sin⁡θ=FBil=152×10×1.5=12\sin \theta \Rightarrow \sin \theta = \frac { F } { B i l } = \frac { 15 } { 2 \times 10 \times 1.5 } = \frac { 1 } { 2 } ⇒ θ=30∘\theta = 30 ^ { \circ }