Question

A current of 10 A is following in a wire of length 1.5 m. A force of 15 N acts on it when it is placed in a uniform magnetic field of 2 T. The angle between the magnetic field and the direction of the current is

• A. 30°
• B. 45°
• C. 60°
• D. 90°

Answer 1

Answer: (A)

30°

Answer 2

$\sin \theta = \frac { 15 } { 10 \times 1.5 \times 2 } = \frac { 1 } { 2 }$ or $\theta = 30 ^ { \circ }$