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Question: A current of 0.1 A circulates around a coil of 100 turns and having a radius equal to 5 cm. The magn...

A current of 0.1 A circulates around a coil of 100 turns and having a radius equal to 5 cm. The magnetic field set up at the centre of the coil is

A

4π×10−54 \pi \times 10 ^ { - 5 } tesla

B

8π×10−58 \pi \times 10 ^ { - 5 } tesla

C

4×10−54 \times 10 ^ { - 5 } tesla

D

2×10−52 \times 10 ^ { - 5 } tesla

Answer

4π×10−54 \pi \times 10 ^ { - 5 } tesla

Explanation

Solution

B=μ0Ni2r=4π×10−7×100×0.12×5×10−2B = \frac { \mu _ { 0 } N i } { 2 r } = \frac { 4 \pi \times 10 ^ { - 7 } \times 100 \times 0.1 } { 2 \times 5 \times 10 ^ { - 2 } } =4π×10−5= 4 \pi \times 10 ^ { - 5 } Tesla