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Question

Physics Question on Current electricity

A current in a wire is given by the equation, I=2t23t+1I = 2t^2 - 3t + 1, the charge through cross section of wire in time interval t=3st = 3\, s to t=5st = 5\,s is

A

32.33C32.33\,C

B

43.34C43.34\,C

C

45.5C45.5\,C

D

42C42\,C

Answer

43.34C43.34\,C

Explanation

Solution

As I=dQdtI=\frac{dQ}{dt} ; dQIdtdQ-Idt ; dQ=(2t23t+1)dtdQ=\left(2t^{2}-3t+1\right)dt dQ=t=3t=5(2t23t+1)dt\int \,dQ=\int \limits ^{t=5}_{t=3}\,\left(2t^{2}-3t+1\right)dt ; Q=[2t333t22+t]35Q=\left[\frac{2t^{3}}{3}-\frac{3t^{2}}{2}+t\right]^{5}_{3} =[25(12527)32(259)+2]=\left[\frac{2}{5}\left(125-27\right)-\frac{3}{2}\left(25-9\right)+2\right] =43.34C=43.34\,C