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Question

Physics Question on Displacement current

A current carrying rectangular loop PQRSP Q R S is made of uniform wire The length PR=QS=5cmP R=Q S=5 \,cm and PQ=RS=100cmP Q=R S=100\, cm If ammeter current reading changes from II to 2I2 I, the ratio of magnetic forces per unit length on the wire PQP Q due to wire RSR S in the two cases respectively (fPQI:fPQ2I)\left(f_{P Q}^I: f_{P Q}^{2 I}\right) is:
A current carrying rectangular loop PQRS is made of uniform wire. The length PR=QS=5 cm and PQ=RS=100cm

A

1:51: 5

B

1:31: 3

C

1:21: 2

D

1:41: 4

Answer

1:41: 4

Explanation

Solution

F∝I1​I2​

F1​:F2I​=1:4

Therefore, The correct answer is option (D): 1:4