Solveeit Logo

Question

Physics Question on Moving charges and magnetism

A current carrying closed loop in the form of a right angle isosceles triangle ABCABC is placed in a uniform magnetic field acting along ABAB. If the magnetic force on the arm BCBC is F\vec{F}, the force on the arm ACAC is

A

2F-\sqrt2\, \vec{F}

B

F-\vec{F}

C

F\vec{F}

D

2F\sqrt2 \,\vec{F}

Answer

F-\vec{F}

Explanation

Solution

From F=I(×B)\vec{ F }= I (\vec{\ell} \times \vec{ B })
FBC=FAC\vec{ F }_{ BC }=-\vec{ F }_{ AC }
FAC=F\vec{ F }_{ AC }=-\vec{ F }