Question

A current 2.0 A is passed for 5 hours through a molten metal salt deposits 22 g of metal (At. wt. =177). The oxidation state of the metal in the metal salt is.

• A.
  • 1
• B.
  • 2
• C.
  • 3
• D.
  • 4

Answer 1

Answer: (C)

• 3

Answer 2

$E_{\text{metal}} = \frac{\text{Weightofmetal} \times 96500}{N ⥂ \text{umberofcoulombs}}$

$= \frac{22.2 \times 96500}{2 \times 5 \times 60 \times 60} = 59.5$

Oxidation number of the metal $= \frac{177}{59.5} = + 3$.