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Question

Physics Question on thermal properties of matter

A cup of tea cools from 65.5C65.5^{\circ} C to 62.5C62.5^{\circ} C in 1 minute in a room at 22.5C22.5^{\circ} C. How long will it take to cool from 46.5C46.5^{\circ} C to 40.5C40.5^{\circ} C in the same room ?

A

4 minutes

B

2 minutes

C

1 minute

D

3 minutes

Answer

4 minutes

Explanation

Solution

dTdt=k(θ=θ0)\frac{dT}{dt} = k (\theta =\theta _0)
I 31=k(6422.5)\frac{3}{1} = k (64 - 22.5)|
31=k(41.5)(1)\frac{3}{1} = k(41.5)\,\,\,\,\,\,\dots(1)
ii 6t=k(43.522.5)\frac{6}{t} = k (43.5 - 22.5)
6t=k(21)(2)\frac{6}{t} = k (21)\,\,\,\,\,\dots(2)
(1)(2)31×t6=41.521\frac{(1)}{(2)} \Rightarrow \frac{3}{1} \times \frac{t}{6} = \frac{41.5}{21}
t=4mint = 4\, min