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Question

Physics Question on System of Particles & Rotational Motion

A cubical block of side L rests on a rough horizontal surface with coefficient of friction μ\mu. A horizontal force F is applied on the block as shown. If the coefficient of friction is sufficiently high, so that the block does not slide before toppling, the minimum force required to topple the block is

A

infinitesimal

B

mg/4

C

mg/2

D

mg(1μ)mg(1-\mu)

Answer

mg/2

Explanation

Solution

At the critical condition, normal reaction N will pass through point P. In this condition τN=0=τfr\tau_N=0=\tau_{fr} (about P) the block will topple when τF>τmg\tau_F > \tau_{mg} or FL>(mg)L2FL > (mg)\frac{L}{2}
F>mg2\therefore F> \frac{mg}{2}
Therefore, the minimum force required to topple the block is
F=mg2F=\frac{mg}{2}