Question
Physics Question on System of Particles & Rotational Motion
A cubical block of side a moving with velocity v on a horizontal smooth plane as shown. It hits a ridge at point O. The angular speed of the block after it hits O is
A
3v/4a
B
3v/2a
C
3/2a
D
Zero
Answer
3v/4a
Explanation
Solution
r2=2a2
Net torque about O is zero.
Therefore, angular momentum (L) about O will be conserved,
or Li=Lf
Mv(2a)=I0?=(Icm+Mr2)?
=\biggl\\{\bigg(\frac{Ma^2}{6}\bigg)+M\bigg(\frac{a^2}{2}\bigg)\biggl\\}?
=32Ma2?
?=4a3v