Question

A cubic solid is made up of two elements $X$ and $Y$ Atoms of $X$ are present on every alternate corner and one at the center of cube $Y$ is at $\frac{1}{3} rd$ of the total faces. The empirical formula of the compound is

• A. $X _2 Y _{1.5}$
• B. $X_{3} Y_2$
• C. $XY _{2, 5}$
• D. $X _{1.5} Y _2$

Answer 1

Answer: (B)

$X_{3} Y_2$

Answer 2

Number of X particles = $4 \times \frac1{8} +1 = 1.5$

Number of Y particles = $6 \times \frac1{3} \times \frac1{2} = 1$

∴ ∴ Empirical formula = $X_{1.5} Y_1 = X_{3} Y_2$

So, the correct option is (B) : $X_{3} Y_2$