Question

A cube of side b has charge q at each of its vertices. The electric field at the center of the cube will be

• A. zero.
• B. $\frac{23q}{b^2}$
• C. $\frac{q}{2b^2}$
• D. $\frac{q}{b^2}$

Answer 1

Answer: (A)

zero.

Answer 2

The electric field is a vector quantity. At the center of the cube, at which the electric fields are equal in magnitude and opposite in directions, due to charges at opposite vertices of the cube, the resultant Electric field at the center would be zero.