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Question

Question: A cube of side \(a\) is subjected to shear stress P as shown in the figure. Determine tangential and...

A cube of side aa is subjected to shear stress P as shown in the figure. Determine tangential and normal stress along diagonal AC.

Explanation

Solution

Stress acting on a body is the force applied per unit area. It causes the shape, area or volume of a body. A shearing force is being applied on the cube; this means that it will change the shape of the cube along its diagonal. The shearing stress is parallel to the area.
Formulas used:
τ=FA\tau =\dfrac{F}{A}

Complete answer:
When a force is applied on a body such that the body gets deformed by slipping between planes, such a force applied per unit area is called the shearing or tangential stress. Its SI unit is Nm2N{{m}^{-2}}. It is given by-
τ=FA\tau =\dfrac{F}{A} - (1)
Here, τ\tau is the shearing stress
FF is the force applied parallel to its side
AA is the displaced area
When a tangential stress, PP is applied on cube of side a, it changes its shape as sown in the figure below

From the above figure,
h=acos45o h=a2 \begin{aligned} & h=a\cos {{45}^{o}} \\\ & \Rightarrow h=\dfrac{a}{\sqrt{2}} \\\ \end{aligned}
The area of the deformed figure will be-
A=b×h A=a×a2 A=a22 \begin{aligned} & A=b\times h \\\ & \Rightarrow A=a\times \dfrac{a}{\sqrt{2}} \\\ & \therefore A=\dfrac{{{a}^{2}}}{\sqrt{2}} \\\ \end{aligned}
The area of the figure is a22\dfrac{{{a}^{2}}}{\sqrt{2}} sq units.
From eq (1), the shearing stress acting on the cube will be-
τ=Pa22 τ=2Pa2 \begin{aligned} & \tau =\dfrac{P}{\dfrac{{{a}^{2}}}{\sqrt{2}}} \\\ & \Rightarrow \tau =\dfrac{\sqrt{2}P}{{{a}^{2}}} \\\ \end{aligned}
Therefore, the shearing or tangential stress acting on the cube is 2Pa2\dfrac{\sqrt{2}P}{{{a}^{2}}}.
As there is no tension or compression acting on the cube, the normal stress acting on it is zero.
Therefore, the tangential stress on the cube is 2Pa2\dfrac{\sqrt{2}P}{{{a}^{2}}} and the normal stress is zero.

Note:
Normal stress occurs when a body is kept under compression or tension due to which its dimensions change. The force applied in a shearing stress is parallel to the cross sectional area. After stress is applied, a restoring force is developed in the body which tends to bring it back to its original shape.