Question
Question: A cube of side \(10cm\) is floating in water kept in a cylindrical beaker of base area \(1500c{m^2}\...
A cube of side 10cm is floating in water kept in a cylindrical beaker of base area 1500cm2. When a mass m is kept on a wooden block the level of water rises in the beaker by 2mm. Find them mass m.
(A)200g
(B)300g
(C)400g
(D)500g
Solution
Here to solve the above question we have to make use of Archimedes principle. The weight immersed in a fluid by a body is equal to the weight of the fluid displaced due to the body. Using the above statements find the displacement. Then by substituting the displacement determine the mass m that is placed in the wooden block.
Formula used:
mg=δVg
δ is the density, V is the volume, g is the acceleration of gravity.
Complete step by step answer:
When a body is immersed in a liquid, this fluid will exert a force due its weight on the body and it will experience an upward force due to the fluid. A balance will be reached when the body displaces fluid weight equal to its weight. This upward force is called the buoyancy force. If they have different density then the body may sink or float. The weight immersed in a fluid by a body is equal to the weight of the fluid displaced due to the body.
Area of the cube A=10×10=100cm2
Water rises by 102cm(2mm)
The weight immersed in a fluid by a body is equal to the weight of the fluid displaced due to the body.
100y=(1500−100)×102
⇒y=2.8cm
Then the mass kept on the wooden block
mg=δVg
⇒mg=δwater×(2.8+0.2)100g
⇒mg=1×(2.8+0.2)100g
⇒m=300g
Then option (B) is the right option.
Note: The weight immersed in a fluid by a body is equal to the weight of the fluid displaced due to the body. A balance will be reached when the body displaces fluid weight equal to its weight. This upward force is called the buoyancy force. Buoyancy is not dependent on mass, density and size of the body.