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Question: A cube of mass m and density D is suspended from the point P by a spring of stiffness k. The system ...

A cube of mass m and density D is suspended from the point P by a spring of stiffness k. The system is kept inside a beaker filled with a liquid of density d. The elongation in the spring, assuming D > d, is :

A

mgk(1dD)\frac { \mathrm { mg } } { \mathrm { k } } \left( 1 - \frac { \mathrm { d } } { \mathrm { D } } \right)

B

C

D

None of these.

Answer

mgk(1dD)\frac { \mathrm { mg } } { \mathrm { k } } \left( 1 - \frac { \mathrm { d } } { \mathrm { D } } \right)

Explanation

Solution

The cube is in equilibrium under three forces as,

(1) spring force kx, where x = elongation of the spring,

(2) gravitational force w, weight of the cube = mg

(3) buoyant force (or upward thrust) imparted by the

liquid on the cube given as F0=Vdg\mathrm { F } _ { 0 } = \mathrm { Vdg } where V = volume of

the immersed portion of the cube. For complete immersion,

V = volume of the cube.For equilibrium of the cube,

kx + = mg

where V = (m/D)