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Question: A cube has a side \(\text{1.2 } \times \text{ 1}\text{0}^{2}\)m. Its volume will be recorded as...

A cube has a side 1.2 × 102\text{1.2 } \times \text{ 1}\text{0}^{2}m. Its volume will be recorded as

A

1.728 × 10-6 m3\text{1.728 } \times \text{ 1}\text{0}^{\text{-6}}\text{ }\text{m}^{3}

B

1.72 × 10-6 m3\text{1.72 } \times \text{ 1}\text{0}^{\text{-6}}\text{ }\text{m}^{3}

C

1.7 × 10-6 m3\text{1.7 } \times \text{ 1}\text{0}^{\text{-6}}\text{ }\text{m}^{3}

D

.72 × 10-6 m3\text{.72 } \times \text{ 1}\text{0}^{\text{-6}}\text{ }\text{m}^{3}

Answer

1.7 × 10-6 m3\text{1.7 } \times \text{ 1}\text{0}^{\text{-6}}\text{ }\text{m}^{3}

Explanation

Solution

V = (1.2 × 10-2)3 = 1.728 × 10-6 m3\text{V }\mathbf{=}\mathbf{\ }\mathbf{(}\text{1.2 }\mathbf{\times}\text{ 1}\text{0}^{\text{-2}}\mathbf{)}^{\mathbf{3}}\mathbf{\ }\mathbf{=}\text{ 1.728 }\mathbf{\times}\text{ 1}\text{0}^{\text{-6}}\text{ }\text{m}^{\mathbf{3}}Rounding upto 2

significant digit

V = 1.7 × 10-6 m3 \text{V } = \text{ 1.7 } \times \text{ 1}\text{0}^{\text{-6}}\text{ }\text{m}^{3}\