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Question

Physics Question on physical world

A cube has a side of length 1.2×10−2m1.2 \times 10^{-2} m. Calculate its volume.

A

1.7×10−6 m31.7 \times 10^{-6} \,m^3

B

1.73×10−6 m31.73 \times 10^{-6}\, m^3

C

1.70×10−6 m31.70 \times 10^{-6} \,m^3

D

1.732×10−6 m31.732 \times 10^{-6} \,m^3

Answer

1.7×10−6 m31.7 \times 10^{-6} \,m^3

Explanation

Solution

Length of the cube, L=1.2×10−2mL =1.2 \times 10^{-2} m ∴\therefore Volume of the cube, V=L3=(1.2×10−2)×(1.2×10−2)×(1.2×10−2)m3V = L ^{3}=\left(1.2 \times 10^{-2}\right) \times\left(1.2 \times 10^{-2}\right) \times\left(1.2 \times 10^{-2}\right) m ^{3} ⇒V=1.728×10−6m3\Rightarrow V =1.728 \times 10^{-6} m ^{3} But as the length contains only 22 significant digits, thus volume must also contain 22 significant digits. Hence, volume of the cube is 1.7×10−6m31.7 \times 10^{-6} m ^{3}