Question
Question: A Cu rod PQ is drawn out normally through the magnetic field \(\overrightarrow{B}\) then <img src="...
A Cu rod PQ is drawn out normally through the magnetic field B then
A
Equal potential on both P and Q occurs and will be positive
B
Equal potential on both P and Q occurs and will be negative
C
The potential at P will be greater then at Q
D
The potential at P will be lesser than at Q
Answer
The potential at P will be greater then at Q
Explanation
Solution
By Fleming's right hand rule direction of induced current in rod PQ is from Q to P, hence P is at higher potential.