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Question

Physics Question on Ray optics and optical instruments

A critical angle for a medium is 60.60^\circ. Then the refractive index of the medium will be

A

3\sqrt 3

B

32\frac{\sqrt 3}{2}

C

23\frac{2}{\sqrt 3}

D

13\frac{1}{\sqrt 3}

Answer

23\frac{2}{\sqrt 3}

Explanation

Solution

μ=1sinC \mu = \frac{1}{\sin\, C}
or μ=1sin60=13/2=23 \mu = \frac{1}{\sin\, 60^\circ}=\frac{1}{\sqrt 3/2 }=\frac{2}{\sqrt 3}