Question

A cricketer can throw a ball to a maximum horizontal distance of 100m. With the same speed how much high above the ground can the cricketer throw the same ball?

• A. 50 m
• B. 100 m
• C. 150 m
• D. 200 m

Answer 1

Answer: (A)

50 m

Answer 2

Let u be the velocity of projection of the ball. The ball will cover maximum horizontal distance when angle of projections with horizontal ,

Then

${R\frac{u^{2}}{g}}_{\max}$

Here, $R_{\max}$

$\therefore\frac{u^{2}}{g} = 100m$ …..(1)

As $v^{2} - u^{2} = 2as$

Here, v = 0 (At highest point velocity is zero)

a = - g, s = H

$\uparrow + \mathrm { ve }$

$\therefore H = \frac{u^{2}}{2g} = \frac{100}{2} = 50m$