Question

A cricketer can throw a ball to a maximum horizontal distance of 100 m. How high above the ground can the cricketer throw the same ball?

• A. 100 m
• B. 50 m
• C. 25 m
• D. 5 m

Answer 1

Answer: (B)

50 m

Answer 2

Let u be the velocity of projections, then

${R\frac{u^{2}}{g}}_{\max}$

Or $u^{2} = 100goru = \sqrt{100g}$

For upward throw of the ball, we have,

$u = \sqrt{100g},v = 0,a = - g$

As $v^{2} - u^{2} = 2asor0 - 100g = 2( - g)s$

$\therefore s = \frac{- 100g}{- 2g} = 50m$