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Question: A cricket player scored \[180\] runs in the first match and \[257\] runs in the second match. Find t...

A cricket player scored 180180 runs in the first match and 257257 runs in the second match. Find the number of runs he should score in the third match so that the average of runs in the three matches be 230230.

Explanation

Solution

Here we will be using the formula of calculating the average of any number which is also known as the arithmetic mean and it is calculated by adding a group of numbers given with the count of that particular number. For example, the average of numbers 22, 33, 55 and 77 will be equals to as below:
Average=2+3+5+74{\text{Average}} = \dfrac{{2 + 3 + 5 + 7}}{4}. By adding the terms in the numerator, we get:
Average=174\Rightarrow {\text{Average}} = \dfrac{{17}}{4}

Complete step-by-step solution:
Step 1: Let the runs scored in the first match be denoted as
x1=180{x_1} = 180. The runs scored by the player in the second match are denoted as x2=257{x_2} = 257 and the third match runs are denoted as x3{x_3} which we need to find.
Step 2: By using the formula of average we get:
Average=x1+x2+x33{\text{Average}} = \dfrac{{{x_1} + {x_2} + {x_3}}}{3}
By substituting the value of x1=180{x_1} = 180and
x2=257{x_2} = 257 in the above expression we get:
Average=180+257+x33\Rightarrow {\text{Average}} = \dfrac{{180 + 257 + {x_3}}}{3}
By substituting the value of average which is
230230 in the above expression we get:
230=180+257+x33\Rightarrow 230 = \dfrac{{180 + 257 + {x_3}}}{3}
Step 3: By doing the addition to the RHS side of the above expression we get:
230=437+x33\Rightarrow 230 = \dfrac{{437 + {x_3}}}{3}
Bringing 33 into the LHS side of the above expression and multiplying it with 230230, we get:
690=437+x3\Rightarrow 690 = 437 + {x_3}
By bringing 437437 into the LHS side of the above expression and subtracting it from 690690, we get:
x3=253\Rightarrow {x_3} = 253

The runs scored by the player in the third match is 253253.

Note: Students need to remember the basic formulas for calculating the average of the terms. There are some important properties of average as below:
When the difference between all the terms is the same then the average equal to the middle term.
If a particular variable xx is added in all the terms then, the average will also be increased by xx
If a particular variable xx is subtracted in all the terms then, the average will also be decreased by xx