Question

A cricket ball of mass 150 gm is moving with a velocity of 12 m/s and is hit by a bat so that the ball is turned back with a velocity of 20 m/s. The force of blow acts for 0.01s on the ball. The average force exerted by the bat on the ball is

• A. 480 N
• B. 600 N
• C. 500 N
• D. 400 N

Answer 1

Answer: (A)

480 N

Answer 2

$v_{1} = - 12m/s$ and $v_{2} = + 20m/s$ [because

direction is reversed]

$m = 150gm = 0.15kg$, $t = 0.01\sec$

Force exerted by the bat on the ball

$F = \frac{m\lbrack v_{2} - v_{1}\rbrack}{t} = \frac{0.15\lbrack 20 - ( - 12)\rbrack}{0.01}$ = 480 Newton