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Question

Physics Question on work, energy and power

A cricket ball of mass 0.25 kg with speed 10 ms1^{-1} collides with a bat and returns with same speed within 0.01 s. The force acted on bat is

A

25 N

B

50 N

C

250 N

D

500 N

Answer

500 N

Explanation

Solution

We have the cricket ball having amass of 0.25 kg and moving with a speed of 10ms1 ms^{-1}, so the change in momentum would be equal to Δp=2mv=2×0.25×10=5kgms1\Delta p = 2mv = 2\times 0.25 \times 10 = 5kg-ms^{-1} and thus the force would be equal to F ΔpΔt=50.01=500N\frac{\Delta p}{\Delta t}=\frac{5}{0.01}=500 N