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Physics Question on Motion in a plane

A cosmonaut is orbiting earth in a spacecraft at an altitude h = 630 km with a speed of 8 kms−1ms^{ - 1}. If the radius of the earth is 6400 km, the acceleration of the cosmonaut is

A

9.10ms−29.10 ms^{ - 2}

B

9.80ms−29.80 ms^{ - 2}

C

10.0ms−210.0 ms^{ - 2}

D

9.88ms−29.88 ms^{ - 2}

Answer

9.10ms−29.10 ms^{ - 2}

Explanation

Solution

Given, v=8 kms−1=8000 ms−1v = 8 \, kms^{ - 1} = 8000 \, ms^{ - 1}, r = (6400 + 630) km = (6400 + 630) ×\times 1000 m a = v2r\frac{ v^2 }{ r} a = (8000)2(6400+630)×1000\frac{ ( 8000)^2 }{ ( 6400 + 630 ) \times 1000 } = 9.10 ms−29.10 \, ms^{ - 2 }