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Question: A cord can bear a maximum force of 100 N without breaking. A body of mass 1 kg tied to one end of a ...

A cord can bear a maximum force of 100 N without breaking. A body of mass 1 kg tied to one end of a cord of length 1 m is revolved in a horizontal plane. What is the maximum linear speed of the body so that the cord does not break

A

10 m/s

B

20 m/s

C

25 m/s

D

30 m/s

Answer

10 m/s

Explanation

Solution

Tension in cord appears due to centrifugal force T=mv2rT = \frac{mv^{2}}{r}and for critical condition this tension will be equal to breaking force (100 N)

mvmax2r\therefore\frac{mv_{\max}^{2}}{r}vmax2100×11v_{\max}^{2\frac{100 \times 1}{1}}vmaxv_{\max}