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Question

Physics Question on Current electricity

A copper wire with a cross-section area of 2×106m22 \times 10^{-6} \, m^2 has a free electron density equal to 5×1022/cm35 \times 10^{22} /cm^{-3}. If this wire carries a current of 16A16\,A, the drift velocity of the electron is

A

1 m/s

B

0.1 m/s

C

0.01 m/s

D

0.001 m/s

Answer

0.001 m/s

Explanation

Solution

Drift velocity, Vd=IneAV_{d}=\frac{I}{n e A}
Given, =n=5×1022/cm3=n=5 \times 10^{22} / cm ^{3}
=5×1022×106/m3=5 \times 10^{22} \times 10^{6} / m ^{3}
e=1.6×1019Ce=1.6 \times 10^{-19} C
A=2×106m2A=2 \times 10^{6} m ^{2}
I=16AI=16\, A
Vd=165×1028×1.6×1019×2×106V_{d}=\frac{16}{5 \times 10^{28} \times 1.6 \times 10^{-19} \times 2 \times 10^{-6}}
=1103=0.001m/s=\frac{1}{10^{3}}=0.001 \,m / s