Question
Question: A copper wire of cross-sectional area \(3.4m{{m}^{2}}\) and length of the wire \(400m\), specific re...
A copper wire of cross-sectional area 3.4mm2 and length of the wire 400m, specific resistivity of copper is 1.7×10−8Ωm. The resistance of the wire is
(A). 20Ω
(B). 200Ω
(C). 2Ω
(D). 2kΩ
Solution
An element opposes the flow of current through it f=due to its resistance. Resistance in circuit along with the potential difference at the ends of circuit determines the current flowing through the circuit. The resistance of a material depends on the type of material as well as its dimensions.
Formula used:
R=Aρl
Complete step-by-step solution:
The property of a material by virtue of which it opposes the flow of current through it is called its resistance. Its SI unit is Ω.
According to Ohm’s law, resistance is given by
R=IV
Here, R is the resistance
V is the potential difference applied at the ends
I is current flowing between the ends
Resistance depends on the type of material as well as the dimensions. Its is also given by-
R=Aρl - (1)
Here, ρ is the resistivity of the material
l is the length
A is the area of cross section
Given, a wire has specific resistivity 1.7×10−8Ωm, its length is 400m and area is 3.4mm2. Substituting given values in eq (1), we get,
R=3.4×10−61.7×10−8×400⇒R=200×10−2Ω∴R=2Ω
The resistance of the wire is 2Ω.
Therefore, the resistance of the wire is 2Ω. Hence, the correct option is (C).
Note:
The specific resistance or resistivity is defined as the resistance of an element of unit length and unit area of cross section. It is a constant quantity and is different for different materials. It depends on temperature. Copper is a metal, hence it is a very low resistance. The resistance in metals is lowest, in semiconductors, the resistance is more than conductors while in insulators, the resistance is the highest.