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Question

Physics Question on Electromagnetic induction

A copper rod AB of length l is rotated about end A with a constant angular velocity ω. The electric field at a distance x from the axis of rotation is

A

mω2xe\frac{m\omega^2x}{e}

B

mωxel\frac{m\omega x}{el}

C

mxω2l\frac{mx}{\omega^2l}

D

meω2x\frac{me}{\omega^2x}

Answer

mω2xe\frac{m\omega^2x}{e}

Explanation

Solution

The correct answer is (A) : mω2xe\frac{m\omega^2x}{e}.