Question

A copper block of mass 50 g is heated to 100⁰C and placed in a block of ice at 0⁰C. The specific heat of copper is 0.1 cal/gm/⁰C and latent heat of ice is 80 cal/gm. The amount of ice melted is –

• A. 6.15 gm
• B. 6.2 gm
• C. 6.25 gm
• D. 6.3 gm

Answer 1

Answer: (C)

6.25 gm

Answer 2

\50 × 0.1 × 30 = m × 80

M = $\frac{50 \times 0.1 \times 100}{80}$= 6.25 gm