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Question: A copper and a steel wire of the same diameter are connected end to end. A deforming force F is appl...

A copper and a steel wire of the same diameter are connected end to end. A deforming force F is applied to this composite wire which causes a total elongation of 1 cm. The two wires will have.

A

The same stress and strain

B

The same stress but different strain

C

The same strain but different stress

D

Different strains and stress

Answer

The same stress but different strain

Explanation

Solution

: Stress=FA= \frac{F}{A}

As each wire is of same diameter, hence the area of cross-section is same for both the wires. As both the wires have the same force (F) and same area of cross-section (1), therefore, stress is same for both the wires.

As young’s modulus,

Y=stressStrainzorStrain=StressYY = \frac{stress}{Strainz}orStrain = \frac{Stress}{Y}

As Y is different for both the wires and stress is same for both the wires, therefore strains is different for both wires.