Question

A coordinations compound X gives plae yellow colour with $AgNO_{3}$solutions while its isomer Y given white precipitate with$BaCl_{2}$. Two compounds are isomer of $CoBrSO_{4}.5NH_{3}.$ What colud be the possible formula of X and Y ?

• A. $X = \lbrack Co(NH_{3})_{5}SO_{4}\rbrack Br,Y = \lbrack Co(NH_{3})_{5}Br\rbrack SO_{4}$
• B. $X = \lbrack Co(NH_{3})_{5}Br\rbrack SO_{4},Y = \lbrack Co(NH_{3})_{5}SO_{4}\rbrack Br$
• C. $X = \lbrack Co(NH_{3})_{5}Br(SO_{4})\rbrack, = \lbrack CoBr(SO_{4})(NH_{3})_{5}\rbrack$
• D. $X = \lbrack Co(Br_{3})_{5}NH_{3}\rbrack SO_{4},Y = \lbrack CoBr(SO_{4})\rbrack NH_{3}$

Answer 1

Answer: (A)

$X = \lbrack Co(NH_{3})_{5}SO_{4}\rbrack Br,Y = \lbrack Co(NH_{3})_{5}Br\rbrack SO_{4}$

Answer 2

$\lbrack Co(\underset{X}{NH_{3}})_{5}SO_{4}\rbrack Br \rightarrow \lbrack Co(NH_{3})_{5}SO_{4}\rbrack^{+} + Br^{-}$

$AgNO_{3} + Br^{-} \rightarrow \underset{paleyellow}{AgBr} + NO_{3}^{-}$

$\lbrack Co(NH_{3})_{5}Br\rbrack SO_{4} \rightarrow \lbrack Co(NH_{3})_{5}Br\rbrack^{2 +} + SO_{4}^{2 -}BaCl_{2} + SO_{4}^{2 -} \rightarrow \underset{Whiteppt}{BaSO_{4}} + 2Cl^{-}$