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Question

Physics Question on Ray optics and optical instruments

A convex mirror of radius of curvature 30 cm forms an image that is half the size of the object. The object distance is:

A

−15 cm

B

45 cm

C

−45 cm

D

15 cm

Answer

−15 cm

Explanation

Solution

Step 1: Given Parameters

Radius of curvature R=30cmR = 30 \, \text{cm}. For a mirror, focal length f=R2=+15cmf = \frac{R}{2} = +15 \, \text{cm} (positive for a convex mirror).

Step 2: Use the Magnification Formula for Mirrors

Given that the image is half the size of the object, the magnification m=12m = \frac{1}{2}. For a convex mirror, a virtual image is formed for a real object, so mm is positive:

m=+12m = +\frac{1}{2}

Step 3: Apply the Mirror Formula

The magnification formula is m=ffum = \frac{f}{f - u}. Substitute m=12m = \frac{1}{2} and f=15cmf = 15 \, \text{cm}:

12=1515u\frac{1}{2} = \frac{15}{15 - u}

Step 4: Solve for uu

15u=30    u=15cm15 - u = 30 \implies u = -15 \, \text{cm}

So, the correct answer is: -15 cm