Solveeit Logo

Question

Question: A convex lens of focal length is \(\dfrac{2}{3}\)times \[R\]. Find the refractive index of the mater...

A convex lens of focal length is 23\dfrac{2}{3}times RR. Find the refractive index of the material.

Explanation

Solution

We are going to find the refractive index of the material with the given focal length is 23\dfrac{2}{3} times RR .We need to discuss the convex lens and the formula used to find the focal length of the convex lens. A lens is a material having one of the surfaces curved. The convex lens containing a surface bulged on one side is called a simple convex lens. Refractive index is defined as the ratio between the velocity of light in a vacuum(c)(c) and the velocity of light in a given substance (v)(v). It is also the ratio between the sine of the angle of incidence (sini)(\sin i) and the angle of refraction (sinr)(\sin r).

Formula used:
Using Len’s maker's formula, the focal length of a lens is given by
1f=(n1)(1R11R2)\dfrac{1}{f} = \left( {n - 1} \right)\left( {\dfrac{1}{{{R_1}}} - \dfrac{1}{{{R_2}}}} \right)
Where,
ff- focal length of a lens
nn- refractive index of the material
R1,R2{R_1},{R_2} - radii of curvature of the lens
Complete step by step solution:
From the given data, the focal length is f=23Rf = \dfrac{2}{3}R.
For convex lens,
R1=+R,R2=R{R_1} = + R,{R_2} = - R.
Applying these values in the above formula,
1f=(n1)(1R11R2)\dfrac{1}{f} = \left( {n - 1} \right)\left( {\dfrac{1}{{{R_1}}} - \dfrac{1}{{{R_2}}}} \right) , this formula becomes
1(23R)=(n1)(1R1R)\Rightarrow \dfrac{1}{{\left( {\dfrac{2}{3}R} \right)}} = \left( {n - 1} \right)\left( {\dfrac{1}{R} - \dfrac{1}{{ - R}}} \right)
32R=(n1)(1R+1R)\Rightarrow \dfrac{3}{{2R}} = \left( {n - 1} \right)\left( {\dfrac{1}{R} + \dfrac{1}{R}} \right)
32R=(n1)(2R)\Rightarrow \dfrac{3}{{2R}} = \left( {n - 1} \right)\left( {\dfrac{2}{R}} \right)
32R×R2=(n1)\Rightarrow \dfrac{3}{{2R}} \times \dfrac{R}{2} = \left( {n - 1} \right),
34=(n1)\Rightarrow \dfrac{3}{4} = \left( {n - 1} \right)
n=(34+1)\Rightarrow n = \left( {\dfrac{3}{4} + 1} \right)
n=(74)\Rightarrow n = \left( {\dfrac{7}{4}} \right)
n=1.75\therefore n = 1.75
From the above calculations, we found that the refractive index of the material n=1.75n = 1.75 when the focal length of the convex lens is,
f=23Rf = \dfrac{2}{3}R.

Note:
The collimated beam, when passing through the convex lens, is focused in a spot. The distance between the lens and the point focused by the converging beam is called focal length and that point is known as the focal point. The convex lenses are in cameras, microscopes, eyeglasses, projectors, etc. The Convex lens is mainly used for converging all incident rays to a particular point.