Question

A converging lens forms an image of an object on a screen. The image is real & has twice the size of the object. If the positions of the screen & the object are interchanged, leaving the lens in its original position, what is the new image size on the screen.

• A. Twice the object size
• B. Same as the object size
• C. Half the object size
• D. Can't say as it depends on the focal length of the lens

Answer 1

Answer: (C)

Half the object size

Answer 2

m₁ m₂ = 1

m₂ =

m₂ = $\frac { 1 } { 2 }$