Solveeit Logo

Question

Question: A converging lens and converging mirror are placed with their principal axis coinciding. Their separ...

A converging lens and converging mirror are placed with their principal axis coinciding. Their separation equals 40cm40cm. A point source s is placed on the principal axis at a distance of 2cm2cm from the lens. It is found that the final beam comes out parallel to the principal axis. The focal length of the lens is 5cm5cm. Find the focal length of the mirror.

Explanation

Solution

Calculate the image formed due to the converging lens. This distance when added to the distance between lens and mirror will become the object distance for the converging mirror. Thus, we can find the focal lengths of mirrors easily.

Formula used:
1f=1v1u 1f=1v+1u \begin{aligned} & \dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u} \\\ & \dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u} \\\ \end{aligned}

Complete answer:

Converging lens is present first, thus, the rays pass through the lens.
For converging lens, object distance, focal length is given as u=2cm,f=5cmu=-2cm,f=5cm.
Applying the lens formula, we get,
1f=1v1u 15=1v12 v=3.33cm.  \begin{aligned} & \dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u} \\\ & \dfrac{1}{5}=\dfrac{1}{v}-\dfrac{1}{-2} \\\ & v=-3.33cm. \\\ & \\\ \end{aligned}
Therefore, the image of the object source formed by the converging lens is 3.33cm3.33cm from the lens on the same side of the object.

As the image is formed on the same side of the object, the distance of object for the converging mirror will become, u1=40+3.33=43.33cm{{u}_{1}}=40+3.33=43.33cm
Given, the final beam of ray coming out of the total system is parallel to the principal axis. We know, if the ray is parallel to the principal axis, the image formed is at infinity. The dame is the case here.
Therefore, the image distance and object distance are ,43.33cm\infty ,43.33cm respectively.
Applying lens formula to the above values, we get,
1f=1v1u 1f=1143.33 f=43.33cm \begin{aligned} & \dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u} \\\ & \dfrac{1}{f}=\dfrac{1}{\infty }-\dfrac{1}{43.33} \\\ & f=43.33cm \\\ \end{aligned}
Therefore, the focal length of the converging mirror is 43.33cm43.33cm.

Additional Information:
The lens formula gives us the relation between object distance, image distance and focal length of the lens. The convex lens is also called a converging lens as the ray’s incident on the lens converges after falling on the lens while the concave lens is called diverging lens as the rays diverge. The lens makers formula was discovered by Descartes.

Note:
In the above problem, the image formed due to the converging lens is on the same side of the object, therefore, the object distance for the converging mirror is the sum of distance between lens and image distance. If in case, the image is formed opposite to the object, the object distance for the error is the subtraction of both the values.