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Question: A convergent beam of light passes through a diverging lens of focal length 0.2 m and comes to focus ...

A convergent beam of light passes through a diverging lens of focal length 0.2 m and comes to focus 0.3 m behind the lens. The position of the point at which the beam would converge in the absence of the lens is :

A

0.12 m

B

0.6 m

C

0.3 m

D

0.15 m

Answer

0.12 m

Explanation

Solution

: Here,

The lens formula,

1v−1u=1f\frac { 1 } { v } - \frac { 1 } { u } = \frac { 1 } { \mathrm { f } }