Question
Question: A continuous random variable X has the P.D.F \(f\left( x \right)=3{{x}^{2}},0\le x\le 1\). The value...
A continuous random variable X has the P.D.F f(x)=3x2,0≤x≤1. The value of a constant λ that satisfies the relation P\left\\{ X\le \lambda \right\\}=P\left\\{ X>\lambda \right\\} is
A. (31)21
B. (21)31
C. (32)21
D. (32)31
Explanation
Solution
We first check if the given P.D.F satisfies the condition of −∞∫∞f(x)dx=1. We take the integration of 0∫13x2dx. We then use the given condition of P\left\\{ X\le \lambda \right\\}=P\left\\{ X>\lambda \right\\} to form the integration part. We solve the equation to find the final solution.
Complete step by step answer:
The given P.D.F is f(x)=3x2,0≤x≤1. The condition for P.D.F is −∞∫∞f(x)dx=1.
Here we take the integration for 0≤x≤1.
We get 0∫13x2dx=1.