Question

A continuous random variable $X$ has the following probability density function:$f(x) = \begin{cases} kx^2(1 - x^3), & 0 \leq x \leq 1 \\\0, & \text{elsewhere}\end{cases}$If the mean of $X$ is 0.64, then the value of $k$ (rounded off to 2 decimal places) is ________________.

Answer 1

The correct Answe is:5.80 or 6.20 Approx