Question

A container of 1 L capacity contains a mixture of 4 g of $O_{2}$and 2 g of $H_{2}$at $O^{0}C$. What will be the total pressure of the mixture?

• A. $50.42$atm
• B. $25.21$atm
• C. $15.2$atm
• D. $12.5$atm

Answer 1

Answer: (B)

$25.21$atm

Answer 2

: Applying $PV = \frac{w}{M}RT$

$Po_{2} = \frac{4}{32} \times \frac{0.0821 \times 273}{1} = 2.81atm$

$P_{H2} = \frac{2}{2} \times 0.0821 \times 273 = 22.4atm$

$P_{total} = Po_{2} + P_{H_{2}} = 2.81 + 22.4 = 25.21atm$