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Chemistry Question on Partial pressure

A container contains 1g H₂ gas and 1g O2 gas. What is the ratio of partial pressure of H₂ and O₂ (PH2/PO2)?

A

16:1

B

8:1

C

4:1

D

1:1

Answer

16:1

Explanation

Solution

The correct option is (A): 16:1
PH2=PTxH2P_{H_2}=P_Tx_{H_2} (PT = total pressure )
(xH2x_{H_2} = mole fraction of H2 )
Po2=PTxO2P_{o_2}=P_{T}x_{O_2} (xO2x_{O_2} = mole fraction of O2 )
PH2PO2=xH2xO2=nH2nO2\frac{P_{H_2}}{P_{O_2}}=\frac{x_{H_2}}{x_{O_2}}=\frac{n_{H_2}}{n_{O_2}}
nH2=12 moln_{H_2}=\frac{1}{2}\ mol
nO2=132n_{O_2}=\frac{1}{32}
PH2PO2=12×1×32\frac{P_{H_2}}{P_{O_2}}=\frac{1}{2\times1}\times32
PH2PO2=322=161\frac{P_{H_2}}{P_{O_2}}=\frac{32}{2}=\frac{16}{1}
Therefore , the ratio is 16:1