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Question: A constant volume gas thermometer shows pressure reading of 50cm and 90cm of mercury at 0°C and 100°...

A constant volume gas thermometer shows pressure reading of 50cm and 90cm of mercury at 0°C and 100°C respectively. When the pressure reading is 60 cm of mercury, the temperature is

A

25°C

B

40°C

C

15°C

D

12.5°C

Answer

25°C

Explanation

Solution

t=(PtP0)(P100P0)×100C=(6050)(9050)×100=25Ct = \frac{(P_{t} - P_{0})}{(P_{100} - P_{0})} \times 100{^\circ}C = \frac{(60 - 50)}{(90 - 50)} \times 100 = 25{^\circ}C