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Question: A constant force acts on a body of mass 0.9 kg at rest for 10s. If the body moves a distance of 250 ...

A constant force acts on a body of mass 0.9 kg at rest for 10s. If the body moves a distance of 250 m, the magnitude of the force is

A

3N3N

B

3.5N3.5N

C

4.0N4.0N

D

4.5N4.5N

Answer

4.5N4.5N

Explanation

Solution

u=0,S=250m,6mut=10sec6muu = 0,S = 250m,\mspace{6mu} t = 10\sec\mspace{6mu}

S=ut+12at2S = ut + \frac{1}{2}at^{2}250=12a[10]2a=5m/s2250 = \frac{1}{2}a\lbrack 10\rbrack^{2} \Rightarrow a = 5m/s^{2}

So, F=ma=0.9×5=4.5NF = ma = 0.9 \times 5 = 4.5N