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Question: A constant force acting on a body of mass of 5 kg change its speed from \(5ms^{- 1}\)to \(10ms^{- 1}...

A constant force acting on a body of mass of 5 kg change its speed from 5ms15ms^{- 1}to 10ms110ms^{- 1}in 10 s without changing the direction of motion. The force acting on the body is :

A

1.5 N

B

2 N

C

2.5 N

D

5 N

Answer

2.5 N

Explanation

Solution

Here m=5kg,u=5ms1,v=10ms1,t=10sm = 5kg,u = 5ms^{- 1},v = 10ms^{- 1},t = 10s

Using v=u+atv = u + at

a=vut=(105)ms110s=0.5ms2a = \frac{v - u}{t} = \frac{(10 - 5)ms^{- 1}}{10s} = 0.5ms^{- 2}

As F=maF = ma

F=(5kg)(0.5ms2)=2.5N\therefore F = (5kg)(0.5ms^{- 2}) = 2.5N