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Question

Physics Question on laws of motion

A constant force acting on a body of mass of 5kg5 \,kg change its speed from 5ms15\, m s^{-1} to 10ms110\, ms^{-1} in 10s10\, s without changing the direction of motion. The force acting on the body is

A

1.5N1.5 \,N

B

2N2 \,N

C

2.5N2.5 \,N

D

5N5\, N

Answer

2.5N2.5 \,N

Explanation

Solution

Here, m=5Kgm=5 Kg, u=5ms1u=5\, m s^{-1}, v=10ms1v=10 \,m s^{-1}, t=10st=10\, s Using v=u+at v=u+a t a=vuta=\frac{v-u}{t} =(105)ms110s=\frac{\left(10-5\right)m s^{-1}}{10 \, s} =0.5ms2=0.5 \,m s^{-2} As F=maF=ma \therefore\, F=(5kg)F=\left(5\, kg\right) (0.5ms2)\left(0.5\,m s^{-2}\right) =2.5N=2.5 \,N